JS校验URL是否合法
checkURL = function (URL) {
var str = URL;
//判断URL地址的正则表达式为:http(s)?://([\w-]+\.)+[\w-]+(/[\w- ./?%&=]*)?
//下面的代码中应用了转义字符"\"输出一个字符"/"
var Expression = /http(s)?:\/\/([\w-]+\.)+[\w-]+(\/[\w- .\/?%&=]*)?/;
var objExp = new RegExp(Expression);
if (objExp.test(str) == true) {
return true;
} else {
return false;
}
}
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